6lab_DONE!

Lab/Lab#6/insert.sql

@@ -1,4 +1,4 @@
-DROP TABLE bd6_employees IF EXISTS;
+DROP TABLE IF EXISTS bd6_employees;
 
 -- CREATE TABLE bd6_departments(
 --   id integer PRIMARY KEY,

Lab/Lab#6/lab6.sql

@@ -0,0 +1,49 @@
+CREATE OR REPLACE PROCEDURE update_salary() AS $$
+DECLARE
+   emp_record bd6_employees%ROWTYPE;
+   counter integer := 0;
+   min_salary bd6_employees.salary_in_euro%TYPE;
+   max_salary bd6_employees.salary_in_euro%TYPE;
+BEGIN
+  -- SELECT MIN(salary_in_euro), MAX(salary_in_euro) INTO min_salary, max_salary FROM bd6_employees;
+   
+   FOR emp_record IN
+   SELECT * FROM (SELECT * FROM bd6_employees ORDER BY salary_in_euro LIMIT 3) AS min_salaries
+   LOOP
+      DELETE FROM bd6_employees WHERE id = emp_record.id;
+      counter := counter + 1;
+   END LOOP;
+   FOR emp_record IN
+   SELECT * FROM (SELECT * FROM bd6_employees ORDER BY salary_in_euro DESC LIMIT 3) AS max_salaries
+   LOOP
+      UPDATE bd6_employees SET salary_in_euro = salary_in_euro + min_salary WHERE id = emp_record.id;
+      counter := counter + 1;
+   END LOOP;
+   
+   RAISE NOTICE 'Successfully updated % bd6_employees.', counter;
+END $$ LANGUAGE plpgsql;
+CALL update_salary();
+
+CREATE OR REPLACE PROCEDURE update_and_delete_salaries() AS $$
+BEGIN
+    -- Увеличение заработной платы
+    WITH lowest_salaries AS (
+        SELECT id, salary_in_euro
+        FROM bd6_employees
+        ORDER BY salary_in_euro
+        LIMIT 10
+    ), highest_salary AS (
+        SELECT max(salary_in_euro) AS max_salary
+        FROM bd6_employees
+    )
+    UPDATE bd6_employees e
+    SET salary_in_euro = e.salary_in_euro + ls.salary_in_euro - (SELECT max_salary FROM highest_salary)
+    FROM lowest_salaries ls
+    WHERE e.id = ls.id;
+
+    -- Удаление сотрудников
+    DELETE FROM bd6_employees WHERE id IN (SELECT id FROM lowest_salaries);
+
+    RAISE NOTICE 'Salaries updated and lowest paid bd6_employees deleted.';
+END;
+$$ LANGUAGE plpgsql;

Lab/Lab#6/lab6_done.sql

@@ -50,6 +50,7 @@ FOR employee_rec IN (
    SELECT last_name, first_name, salary_in_euro 
    FROM bd6_employees 
    ORDER BY salary_in_euro) 
+
 LOOP
    current_salary := employee_rec.salary_in_euro;
 
@@ -74,32 +75,42 @@ CALL print_employees();
 большой заработной платой. 2-я с конца заработная плата должна добавиться
 к человеку со второй по размеру заработной платой и т.д. */
 
-CREATE OR REPLACE PROCEDURE update_salary() AS $$
+CREATE OR REPLACE FUNCTION rearrange_salaries() RETURNS VOID AS $$
 DECLARE
-   emp_record bd6_employees%ROWTYPE;
-   counter integer := 0;
-   min_salary bd6_employees.salary_in_euro%TYPE;
-   max_salary bd6_employees.salary_in_euro%TYPE;
+    salaries RECORD;
+	small NUMERIC[];
+	larg NUMERIC[];
+	const CONSTANT INTEGER = 10;
 BEGIN
-   SELECT MIN(salary_in_euro), MAX(salary_in_euro) INTO min_salary, max_salary FROM bd6_employees;
-   
-   FOR emp_record IN
-   SELECT * FROM (SELECT * FROM bd6_employees ORDER BY salary_in_euro LIMIT 3) AS min_salaries
-   LOOP
+    FOR salaries IN 
+        SELECT id, salary_in_euro
+        FROM bd6_employees 
+        ORDER BY salary_in_euro 
+        LIMIT const
+	LOOP
+		small = array_append(small, (SELECT salary_in_euro FROM bd6_employees WHERE id = salaries.id));
+    	DELETE FROM bd6_employees
+    	WHERE id = salaries.id;
+	END LOOP;
 
-      DELETE FROM bd6_employees WHERE id = emp_record.id;
-      counter := counter + 1;
-   END LOOP;
-   FOR emp_record IN
-   SELECT * FROM (SELECT * FROM bd6_employees ORDER BY salary_in_euro DESC LIMIT 3) AS max_salaries
-   LOOP
-      UPDATE bd6_employees SET salary_in_euro = salary_in_euro + min_salary WHERE id = emp_record.id;
-      counter := counter + 1;
-   END LOOP;
-   
-   RAISE NOTICE 'Successfully updated % bd6_employees.', counter;
-END $$ LANGUAGE plpgsql;
-CALL update_salary();
+    FOR salaries IN 
+        SELECT id, salary_in_euro
+        FROM bd6_employees 
+        ORDER BY salary_in_euro DESC 
+        LIMIT const
+	LOOP
+		larg = array_append(larg, (SELECT id FROM bd6_employees WHERE id = salaries.id));
+	END LOOP;
+	
+	FOR i IN 1..const
+	LOOP
+        UPDATE bd6_employees
+        SET salary_in_euro = salary_in_euro + small[i]
+        WHERE id = larg[i];
+    END LOOP;
+END;
+$$ LANGUAGE plpgsql;
+SELECT rearrange_salaries();
 
 -- Task 4 --
 /* Создайте таблицу spiral с 5 полями f1, f2, f3, f4, f5 – целые числа.

Lab/Lab#6/test3.sql

@@ -1,26 +1,36 @@
-CREATE OR REPLACE PROCEDURE update_salary() AS $$
+CREATE OR REPLACE FUNCTION rearrange_salaries() RETURNS VOID AS $$
 DECLARE
-   emp_record bd6_employees%ROWTYPE;
-   counter integer := 0;
-   min_salary bd6_employees.salary_in_euro%TYPE;
-   max_salary bd6_employees.salary_in_euro%TYPE;
+    salaries RECORD;
+	small NUMERIC[];
+	larg NUMERIC[];
+	const CONSTANT INTEGER = 10;
 BEGIN
-   SELECT MIN(salary_in_euro), MAX(salary_in_euro) INTO min_salary, max_salary FROM bd6_employees;
-   
-   FOR emp_record IN
-   SELECT * FROM (SELECT * FROM bd6_employees ORDER BY salary_in_euro LIMIT 3) AS min_salaries
-   LOOP
+    FOR salaries IN 
+        SELECT id, salary_in_euro
+        FROM bd6_employees 
+        ORDER BY salary_in_euro 
+        LIMIT const
+	LOOP
+		small = array_append(small, (SELECT salary_in_euro FROM bd6_employees WHERE id = salaries.id));
+    	DELETE FROM bd6_employees
+    	WHERE id = salaries.id;
+	END LOOP;
 
-      DELETE FROM bd6_employees WHERE id = emp_record.id;
-      counter := counter + 1;
-   END LOOP;
-   FOR emp_record IN
-   SELECT * FROM (SELECT * FROM bd6_employees ORDER BY salary_in_euro DESC LIMIT 3) AS max_salaries
-   LOOP
-      UPDATE bd6_employees SET salary_in_euro = salary_in_euro + min_salary WHERE id = emp_record.id;
-      counter := counter + 1;
-   END LOOP;
-   
-   RAISE NOTICE 'Successfully updated % bd6_employees.', counter;
-END $$ LANGUAGE plpgsql;
-CALL update_salary();
+    FOR salaries IN 
+        SELECT id, salary_in_euro
+        FROM bd6_employees 
+        ORDER BY salary_in_euro DESC 
+        LIMIT const
+	LOOP
+		larg = array_append(larg, (SELECT id FROM bd6_employees WHERE id = salaries.id));
+	END LOOP;
+	
+	FOR i IN 1..const
+	LOOP
+        UPDATE bd6_employees
+        SET salary_in_euro = salary_in_euro + small[i]
+        WHERE id = larg[i];
+    END LOOP;
+END;
+$$ LANGUAGE plpgsql;
+SELECT rearrange_salaries();