done 7lab

Lab#7/lab7.sql

@@ -0,0 +1,128 @@
+-- Лабораторная работа №7 || Антипенко, Дробышевский || Вариант 4 -- 
+
+-- Задание 1
+-- • Создайте две таблицы: people и people_log. Первая таблица должна
+-- содержать поля идентификатор (id), имя (first_name), фамилия
+-- (last_name), дата рождения (birthday), текущее состояние счёта
+-- (amount). Поле id – это первичный ключ. Поле amount – это
+-- действительное число. Вторая таблица должна содержать поля:
+-- идентификатор человека (person_id) дата операции (operation_date),
+-- сумма (sum). Поле person_id должно быть ограничено, как внешний
+-- ключ, ссылающийся на поле id таблицы people. Поле operation_date
+-- должно позволить сохранять дату и время. Поле sum – это
+-- действительное число. Заполните таблицы people и people_log
+-- несколькими записями (не менее 5 на таблицу).
+
+		CREATE TABLE people (
+			id SERIAL PRIMARY KEY,
+			first_name VARCHAR(50),
+			last_name VARCHAR(50),
+			birthday DATE,
+			amount DECIMAL(10, 2)
+		);
+
+		CREATE TABLE people_log (
+			id SERIAL PRIMARY KEY,
+			person_id INTEGER REFERENCES people(id),
+			operation_date TIMESTAMP,
+			sum DECIMAL(10, 2)
+		);
+
+		INSERT INTO people (first_name, last_name, birthday, amount) 
+		VALUES 
+		('Иван', 'Иванов', '1985-05-15', 1000.50),
+		('Петр', 'Петров', '1990-10-20', 750.25),
+		('Мария', 'Сидорова', '1978-12-03', 3000.75),
+		('Елена', 'Козлова', '1989-08-27', 200.00),
+		('Алексей', 'Смирнов', '1980-04-18', 1500.00);
+
+		INSERT INTO people_log (person_id, operation_date, sum) 
+		VALUES 
+		(1, '2023-09-20 10:15:00', 250.00),
+		(3, '2023-10-01 15:30:00', 800.50),
+		(2, '2023-11-05 08:45:00', 100.25),
+		(4, '2023-11-25 12:00:00', 50.00),
+		(5, '2023-12-02 18:20:00', 300.00);
+		
+SELECT * FROM people;
+SELECT * FROM people_log;
+
+
+-- Задание 2
+-- • Напишите процедуру или функцию statement_of_acount, которая на
+-- основе двух параметров: даты начала периода и даты окончания
+-- периода печатала бы на экран данные (operation_date и sum) трёх самых
+-- крупных операций с положительной суммой, трёх самых крупных
+-- операций с отрицательной суммой и данные об общем числе операций
+-- и среднем значении суммы.
+
+CREATE OR REPLACE PROCEDURE statement_of_acount(start_date DATE, end_date DATE) AS $$ 
+DECLARE 
+    pos_sum RECORD;
+    neg_sum RECORD;
+    total_count INTEGER;
+    avg_amount NUMERIC;
+	const CONSTANT INTEGER = 3;
+	
+BEGIN 
+    FOR pos_sum IN (
+        SELECT operation_date, sum
+        FROM people_log
+        WHERE operation_date BETWEEN start_date AND end_date AND sum > 0
+        ORDER BY sum DESC
+        LIMIT const
+    ) LOOP
+        RAISE INFO 'Positive: %, Sum: %', pos_sum.operation_date, pos_sum.sum;
+    END LOOP;
+
+    FOR neg_sum IN (
+        SELECT operation_date, sum
+        FROM people_log
+        WHERE operation_date BETWEEN start_date AND end_date AND sum < 0
+        ORDER BY sum ASC
+        LIMIT const
+    ) LOOP
+        RAISE INFO 'Negative: %, Sum: %', neg_sum.operation_date, neg_sum.sum;
+    END LOOP;
+
+    SELECT COUNT(*) INTO total_count
+    FROM people_log
+    WHERE operation_date BETWEEN start_date AND end_date;
+
+    SELECT AVG(sum) INTO avg_amount
+    FROM people_log
+    WHERE operation_date BETWEEN start_date AND end_date;
+
+    RAISE INFO 'Total number of operations: %', total_count;
+    RAISE INFO 'Average amount of transactions: %', avg_amount;
+
+END $$ LANGUAGE plpgsql; 
+
+CALL statement_of_acount('2023-01-01', '2023-12-31');
+
+
+-- Задание 3
+-- • Напишите процедуру или функцию account_operation, которая на
+-- основе двух параметров: идентификатора человека и суммы вносит
+-- изменения в таблицы people и people_log. В таблице people у человека с
+-- указанным в качестве параметра идентификатором состояние счёта
+-- должно измениться на указанную в качестве параметра сумму. В
+-- таблицу people_log должна быть добавлена запись с указанным в
+-- качестве параметра идентификатором человека, текущей датой и
+-- временем и указанной в качестве параметра суммой.
+
+
+
+CREATE OR REPLACE PROCEDURE account_operation(new_id integer, add_sum numeric) AS $$ 
+DECLARE
+BEGIN 
+    UPDATE people 
+	SET amount = amount + add_sum 
+	WHERE id = new_id;
+    INSERT INTO people_log (person_id, operation_date, sum) VALUES (new_id, CURRENT_TIMESTAMP(0), add_sum);
+END $$ LANGUAGE plpgsql; 
+
+CALL account_operation(5, 1000000);
+
+SELECT * FROM people;
+SELECT * FROM people_log;

Lab#7/lab7_aa.sql

@@ -0,0 +1,99 @@
+DROP TABLE people_log IF EXISTS;
+DROP TABLE people IF EXISTS;
+
+
+--1--
+CREATE TABLE people (
+    id SERIAL PRIMARY KEY,
+    first_name VARCHAR(64),
+    last_name VARCHAR(64),
+    birthday DATE,
+    amount NUMERIC(10,2)
+);
+
+CREATE TABLE people_log (
+    person_id INTEGER REFERENCES people(id),
+    operation_date TIMESTAMP,
+    sum NUMERIC(10,2)
+);
+
+INSERT INTO people (first_name, last_name, birthday, amount) 
+VALUES ('Andrey', 'Ad', '2004-03-09', 1000.00),
+       ('Sanal', 'Bat', '2004-12-15', 2000.00),
+       ('Alex', 'Yak', '2004-08-10', 3000.00),
+       ('Dima', 'Klev', '2004-04-25', 4000.00),
+       ('David', 'Dav', '2001-11-30', 5000.00),
+	   ('Reno', 'G', '2004-08-28', 6000.00),
+       ('Ilya', 'Zim', '2005-01-06', 7000.00),
+       ('Sema', 'Akh', '2005-12-01', 8000.00);
+	   
+
+INSERT INTO people_log ( person_id, operation_date, sum) 
+VALUES
+(1, '2022-01-05 17:15:00', 100.00),
+(2, '2022-01-06 17:30:00', 300.00),
+(3, '2022-01-07 17:45:00', 300.00),
+(4, '2022-01-08 18:00:00', 400.00),
+(5, '2022-01-09 18:15:00', 500.00),
+(6, '2022-01-10 17:15:00', -100.00),
+(7, '2022-01-12 17:15:00', -400.00),
+(8, '2022-01-29 17:15:00', -200.00);
+
+
+
+SELECT * FROM people;
+SELECT * FROM people_log; 
+
+
+--2--
+
+CREATE OR REPLACE PROCEDURE statement_of_acount(start_date DATE, end_date DATE) AS $$ 
+DECLARE 
+    pos_sum RECORD;
+    neg_sum RECORD;
+    total_count INTEGER;
+    avg_amount NUMERIC;
+BEGIN 
+    FOR pos_sum IN (
+        SELECT operation_date, sum
+        FROM people_log
+        WHERE operation_date BETWEEN start_date AND end_date AND sum > 0
+        ORDER BY sum DESC
+        LIMIT 3
+    ) LOOP
+        RAISE INFO 'Положительная операция: %, Сумма: %', pos_sum.operation_date, pos_sum.sum;
+    END LOOP;
+
+    FOR neg_sum IN (
+        SELECT operation_date, sum
+        FROM people_log
+        WHERE operation_date BETWEEN start_date AND end_date AND sum < 0
+        ORDER BY sum ASC
+        LIMIT 3
+    ) LOOP
+        RAISE INFO 'Отрицательная операция: %, Сумма: %', neg_sum.operation_date, neg_sum.sum;
+    END LOOP;
+
+    SELECT COUNT(*) INTO total_count
+    FROM people_log
+    WHERE operation_date BETWEEN start_date AND end_date;
+
+    SELECT AVG(sum) INTO avg_amount
+    FROM people_log
+    WHERE operation_date BETWEEN start_date AND end_date;
+
+    RAISE INFO 'Общее количество операций: %', total_count;
+    RAISE INFO 'Средняя сумма операций: %', avg_amount;
+
+END $$ LANGUAGE plpgsql; 
+CALL statement_of_acount('2022-01-01', '2022-11-12');
+
+--3--
+CREATE OR REPLACE PROCEDURE account_operation(new_id integer, summa numeric) AS $$ 
+DECLARE
+BEGIN 
+    UPDATE people SET amount = amount + summa WHERE id = new_id;
+    INSERT INTO people_log (person_id, operation_date, sum) VALUES (new_id, CURRENT_TIMESTAMP(0), summa);
+END $$ LANGUAGE plpgsql; 
+
+CALL account_operation(1, 100);

Lab/Lab#6/lab6_done.sql

@@ -9,41 +9,23 @@ b) Напишите программу на языке PL/SQL, печатающ
 и имя сотрудника с идентификатором 1 и всех его подчинённых, как
 прямых, так и подчинённых более низкого ранга. */
 
--- CREATE OR REPLACE PROCEDURE department_names() AS $$
--- DECLARE d_attrs RECORD; 
--- BEGIN
-
--- FOR d_attrs IN WITH RECURSIVE tmp AS ( 
---     SELECT id, first_name, last_name, manager_id, 1 AS level 
---     FROM bd6_employees 
---     WHERE manager_id = 1 or id = 1 
---     UNION ALL 
---     SELECT e.id, e.first_name, e.last_name, e.manager_id, t.level + 1 
---     FROM bd6_employees e JOIN tmp t ON e.manager_id = t.id ) 
-
--- SELECT * FROM tmp 
--- LOOP 
---     RAISE INFO ' % % ', d_attrs.first_name, d_attrs.last_name; 
--- END LOOP; 
--- END $$ LANGUAGE plpgsql; 
--- CALL department_names();
-
 -- Пункт а)
 WITH RECURSIVE tmp AS (
-	SELECT id, first_name, last_name, manager_id, 1 AS level
+
-	FROM bd6_employees
+  SELECT id, first_name, last_name, manager_id, 1 AS level
-	WHERE manager_id = 1 OR id = 1
+  FROM bd6_employees
-  UNION ALL
+  WHERE id = 1
-	SELECT e.id, e.first_name, e.last_name, e.manager_id, t.level + 1
+  UNION all
+  SELECT e.id, e.first_name, e.last_name, e.manager_id, t.level + 1
   FROM bd6_employees e
   JOIN tmp t ON e.manager_id = t.id 
 )
-SELECT id, first_name, last_name
+SELECT * 
 FROM tmp
-GROUP BY id, first_name, last_name;
+;
 
 -- Пункт б)
-CREATE OR REPLACE PROCEDURE department_names(integer) AS $$
+CREATE OR REPLACE PROCEDURE depa(integer) AS $$
 DECLARE 
 	d_attrs RECORD;
 	i integer;
@@ -59,13 +41,12 @@ FOR d_attrs IN
 	IF d_attrs.manager_id=$1 THEN
 	 	RAISE INFO ' % % % % ', d_attrs.first_name, d_attrs.last_name, d_attrs.id, d_attrs.manager_id;   
 		l:= d_attrs.id;
-    	CALL department_names(l); 
+    	CALL depa(l); 
 	END IF;
 	END LOOP; 
 END $$ LANGUAGE plpgsql; 
 
-
+CREATE OR REPLACE PROCEDURE dep(integer) AS $$
-CREATE OR REPLACE PROCEDURE department_names2(integer) AS $$
 DECLARE
 	d_attrs RECORD;
 	BEGIN
@@ -85,10 +66,9 @@ DECLARE
 	RAISE INFO ' % % % % ', d_attrs.first_name, d_attrs.last_name, d_attrs.id, d_attrs.manager_id;
     END IF;
 	END LOOP; 
-CALL department_names($1);
+CALL depa($1);
 END $$ LANGUAGE plpgsql; 
-CALL department_names2(4);  
+CALL dep(1);   
-
 
 -- Task 2 --
 /* Напишите программу на языке PL/SQL, выбирающую строки из таблицы
@@ -100,6 +80,8 @@ employees в порядке возрастания заработной плат
 увеличивается на остаток от округления, полученный от предыдущего
 сотрудника, а затем округляется до сотен в меньшую сторону. */ 
 
+UPDATE bd6_employees SET salary_in_euro = 299 WHERE id = 3;
+
 CREATE OR REPLACE PROCEDURE print_employees() AS $$
 DECLARE
 current_salary INTEGER;
@@ -107,52 +89,28 @@ m_salary INTEGER;
 mod_salary INTEGER := 0;
 employee_rec RECORD;
 BEGIN
-FOR employee_rec IN (
+FOR employee_rec IN 
+	(
    SELECT last_name, first_name, salary_in_euro 
    FROM bd6_employees 
-   ORDER BY salary_in_euro) 
+   ORDER BY salary_in_euro
+	) 
 
 LOOP
-   current_salary := employee_rec.salary_in_euro;
+	current_salary := employee_rec.salary_in_euro;
 	
-   IF mod_salary=0 THEN
+	m_salary := ((current_salary + mod_salary) / 100) * 100;
-      m_salary := (current_salary / 100) * 100;
-   ELSE
-      m_salary := ((current_salary + mod_salary) / 100) * 100;
-END IF;
 
 RAISE NOTICE 'Employee: % % || Modified Salary: %', employee_rec.last_name, employee_rec.first_name, m_salary;
+mod_salary := mod(current_salary + mod_salary,100);
 END LOOP;
 END $$ LANGUAGE plpgsql;
 
 CALL print_employees();
-CREATE OR REPLACE PROCEDURE print_employees() AS $$
+SELECT * 
-DECLARE
+FROM bd6_employees
-current_salary INTEGER;
+ORDER BY salary_in_euro;
-m_salary INTEGER;
-mod_salary INTEGER := 0;
-employee_rec RECORD;
-BEGIN
-FOR employee_rec IN (
-   SELECT last_name, first_name, salary_in_euro 
-   FROM bd6_employees 
-   ORDER BY salary_in_euro) 
 
-LOOP
-   current_salary := employee_rec.salary_in_euro;
-
-   IF mod_salary=0 THEN
-      m_salary := (current_salary / 100) * 100;
-   ELSE
-      m_salary := ((current_salary + mod_salary) / 100) * 100;
-END IF;
-
-RAISE NOTICE 'Employee: % %, Modified Salary: %', employee_rec.last_name, employee_rec.first_name, m_salary;
-mod_salary := current_salary - m_salary;
-END LOOP;
-END $$ LANGUAGE plpgsql;
-
-CALL print_employees();
 
 -- Task 3 -- 
 /* Напишите программу на языке PL/SQL, удаляющую 10 сотрудников с
@@ -167,7 +125,7 @@ DECLARE
     salaries RECORD;
 	small NUMERIC[];
 	larg NUMERIC[];
-	const CONSTANT INTEGER = 10;
+	const CONSTANT INTEGER = 3;
 BEGIN
     FOR salaries IN 
         SELECT id, salary_in_euro
@@ -242,26 +200,42 @@ SELECT * FROM dep_staff_counts;
 
 
 
-CREATE OR REPLACE PROCEDURE department_names(integer) AS $$DECLARE d_attrs RECORD;
+CREATE OR REPLACE PROCEDURE department_names(integer) AS $$
-i integer;l integer;
+DECLARE 
+	d_attrs RECORD;
+	i INTEGER;
+	l INTEGER;
 BEGIN
-FOR d_attrs IN (   SELECT id,last_name, first_name, manager_id
+FOR d_attrs IN 
-   FROM bd6_employees order by manager_id )   
+	(
-   LOOP
+	SELECT id,last_name, first_name, manager_id
-      if d_attrs.manager_id=$1 then
+	FROM bd6_employees order by manager_id 
-    RAISE INFO ' % % % % ', d_attrs.first_name, d_attrs.last_name, d_attrs.id, d_attrs.manager_id;    l:= d_attrs.id;
+	)   
-    call department_names(l);    end if;
+	LOOP
+		IF d_attrs.manager_id=$1 THEN
+    		RAISE INFO ' % % % % ', d_attrs.first_name, d_attrs.last_name, d_attrs.id, d_attrs.manager_id;    
+			l:= d_attrs.id;
+    	CALL department_names(l);    
+	END IF;
 END LOOP; 
 END $$ LANGUAGE plpgsql; 
 
 
 CREATE OR REPLACE PROCEDURE department_names2(integer) AS $$
 DECLARE d_attrs RECORD;
-BEGINFOR d_attrs IN (
+BEGIN
-   SELECT id,last_name, first_name, manager_id   FROM bd6_employees order by manager_id )
+	FOR d_attrs IN 
+	(
+	SELECT id,last_name, first_name, manager_id   
+	FROM bd6_employees 
+	order by manager_id 
+	)
       
 LOOP   
-   if d_attrs.id=$1 then    RAISE INFO ' % % % % ', d_attrs.first_name, d_attrs.last_name, d_attrs.id, d_attrs.manager_id;
+	if d_attrs.id=$1 then    
-    end if;END LOOP; 
+	RAISE INFO ' % % % % ', d_attrs.first_name, d_attrs.last_name, d_attrs.id, d_attrs.manager_id;
-CALL department_names($1);END $$ LANGUAGE plpgsql; 
+	end if;
+	END LOOP; 
+CALL department_names($1);
+END $$ LANGUAGE plpgsql; 
 CALL department_names2(4);