added lab4

Lab/Lab#2/var2.sql

@@ -3,7 +3,7 @@
 /* Задание 1 */
 SELECT 
     (first_name || ' ' || last_name) AS "ФИО",
-    salary AS "ОКЛАД",
+    to_char(salary, '9999999D99') AS "ОКЛАД",
     trunc(salary*0.87) AS "Оклад минус подоходный"
 FROM employees;
 
@@ -12,10 +12,10 @@ SELECT
     first_name AS "Имя",
     last_name AS "Фамилия",
     job_id AS "Должность", 
-    hire_date AS "Дата приема на работу"
+    to_char(hire_date, 'DD.MM.YYYY') AS "Дата приема на работу"
 FROM employees
 WHERE job_id IN ('AD_PRES', 'AD_VP', 'AD_ASST')
-AND hire_date BETWEEN SYMMETRIC
+OR hire_date BETWEEN
 '1995-01-01' AND '2023-01-01'
 LIMIT 5;
 
@@ -23,11 +23,11 @@ LIMIT 5;
 SELECT 
 	first_name AS "Имя",
 	last_name AS "Фамилия",
-	job_id AS "Должность", 
+	to_char(salary, '99999D99') AS "Оклад", 
 	to_char(hire_date, 'DD.MM.YYYY') AS "Дата приема на работу",
 	
-	EXTRACT(month from now()) + EXTRACT(year from now())*12
-	- EXTRACT(month from hire_date) - EXTRACT(year from hire_date)*12
+	EXTRACT(month from age(now(), hire_date)) 
+	+ EXTRACT(year from age(now(), hire_date))*12
 	as "Проработано месяцев"
 
 FROM employees;

Lab/Lab#3/lab3.sql

@@ -0,0 +1,63 @@
+/* Лабораторная работа №3 | Вариант 4 | Антипенко, Дробышевский */
+
+SELECT * FROM departments;
+SELECT * FROM employees;
+SELECT * FROM jobs;
+
+/* Задание 1 */
+SELECT 
+	e.first_name AS "FIRST_NAME",
+	e.last_name AS "LAST_NAME", 
+	d.department_name AS "DEPARTMENT_NAME"
+FROM employees e, departments d
+WHERE e.department_id = d.department_id AND d.department_name IN ('IT', 'Sales');
+
+/* Задание 2 */
+SELECT 
+	e.first_name AS "FIRST_NAME",
+	e.last_name AS "LAST_NAME", 
+	trunc(e.salary) AS "SALARY",
+	d.department_name AS "DEPARTMENT_NAME",
+	j.job_title AS "JOB_TITLE"
+FROM employees e, jobs j, departments d
+WHERE e.department_id = d.department_id AND e.job_id = j.job_id
+AND e.salary > 10000
+ORDER BY e.salary ASC;
+
+/* Задание 3 */
+SELECT
+	e.first_name AS "Имя",
+	e.last_name AS "Фамилия", 
+	to_char(e.salary, '99999D99') AS "Оклад",
+	trunc(j.min_salary) AS "Мин.оклад"
+FROM employees e, jobs j
+WHERE e.job_id = j.job_id AND j.min_salary*1.2 >= e.salary;
+
+/* Задание 4 */
+SELECT
+	last_name AS "Фамилия_Р",
+	first_name AS "Имя",
+	to_char(salary, '99999D99') AS "Оклад"
+FROM employees
+WHERE salary > (
+	SELECT
+		AVG(salary)
+	FROM employees
+)
+ORDER BY salary ASC;
+
+/* Задание 5 */
+SELECT 
+	e.first_name AS "Имя",
+    e.last_name AS "Фамилия",
+    e.job_id AS "Должность",
+	to_char(e.salary, '999999D99') AS "Оклад"
+FROM employees e
+/*WHERE e.job_id = j.job_id AND e.salary = j.max_salary*/
+WHERE e.salary, e.job_id IN (
+	SELECT 
+		max_salary,
+		job_id
+	FROM jobs
+);
+	 

Lab/Lab#4/lab4.sql

@@ -0,0 +1,37 @@
+CREATE table staff(
+	id integer primary key,
+	name varchar(64) NOT NULL,
+	department varchar(64) NOT NULL
+);
+
+CREATE SEQUENCE staff_id_seq
+	START WITH 12
+	CYCLE
+	INCREMENT BY 8
+	CACHE 100;
+	
+
+INSERT INTO staff VALUES
+	(nextval('staff_id_seq'), 'Ivan Makarenko', 'Director');
+	
+INSERT INTO staff
+	(SELECT nextval('staff_id_seq'), last_name, department_name
+	 FROM employees e JOIN departments d ON e.department_id = d.department_id);
+	 
+UPDATE staff SET department = 'Innovations department'
+	WHERE id < 40;
+	
+DELETE FROM staff 
+	WHERE name ILIKE('%K%');
+	
+WITH RECURSIVE tmp AS (
+  SELECT employee_id, first_name, last_name, manager_id, 1 AS level
+  FROM employees
+  WHERE manager_id = 100
+  UNION ALL
+  SELECT e.employee_id, e.first_name, e.last_name, e.manager_id, t.level + 1
+  FROM employees e
+  JOIN tmp t ON e.manager_id = t.employee_id
+)
+SELECT first_name, last_name
+FROM tmp;

Practice/SR/var1.sql

@@ -0,0 +1 @@
+SELECT name FROM departments